How is JEE Main Percentile Calculated?

JEE Main is completely shifted to computer based test (CBT) from 2019 while the exam will be conducted across multiple days in different shifts. The important topic of discussion is now around JEE Main score normalization and how scores are determined for the grades. National Testing Agency, under whose supervision the examination is going to be carried out, has published pertinent information on normalization and how JEE Main Percentile will be calculated.

The other significant aspects like groundwork of the position listing, inter-se-merit guiding principles have also been announced. Check below the procedure of JEE Main Score Normalization; how scores are premeditated to allocate the positions.

In view of the fact that JEE Main 2019 will be conducted on diverse days and sessions, the issue of retaining correspondence amid the dissimilar sets of question papers appears to the forefront. It is expected that some aspirants will get a difficult paper while some may get a simple one.

To make certain that no candidate is at an inconvenience or, advantage from this, normalization of the marks gained in JEE Main 2019 will be made compulsory for the reason of standing. NTA will grade students on the strength of their percentile scores that will be counted as indicated by a fixed method.

What is the Percentile Score?

Percentile scores are founded on the comparative presentation of all those aspirants who appear for the test. It will be obtained after converting the scores into a degree ranging from 100 to 0 for each one session of the examinees. Percentile Score demonstrates the percentage of candidates who have achieved equivalent to or less than a specific percentile in an examination. It is the standardized score and not the raw marks.

After normalization, every topper of a session will obtain the similar percentile of 100 which is the appropriate one. Also, the scores between the lowest and highest ones are also altered to the relevant percentiles. As the computation is for each session, all the uppermost raw scores will have normalized Percentile Score of 100 for their individual sessions.

Preparation of JEE Main 2019 Result for each session

  • Step 1: Preparation of the Raw Scores
    • The marks attained by each candidate for every right answer for all subjects (Math, Physics, and Chemistry) will be added to get there at the raw scores
  • Step 2: The Percentile Scores for each of the subject and total percentile score will be prepared

Inter-se-merit to resolve tie:

While two or more candidates get identical Percentile Scores then ranking will be as follows:

  • Candidates who get Percentile Score in Mathematics will be ranked higher
  • Candidates who get Percentile Score in Physics will be ranked higher
  • Candidates who get Percentile Score in Chemistry will be ranked higher
  • According to the Date of Birth, the older candidate will be ranked higher
  • If the tie is yet unsettled, the similar position will be given to the candidates

JEE Main 2019 Rank list

The grade record for JEE Main 2019 will be declared subsequent to both January and April attempts are judged for candidates who have appeared in both the exams.

First attempt compilation of NTA Scores:

Following the JEE Main, I will terminate in January, the end result that will be announced on January 31 will present the four NTA scores – meant for all of the three subjects(Mathematics, Physics, and Chemistry) and the entire NTA score for that attempt. NTA scores will be the percentile scores considered as stated before.

Second attempt compilation of NTA Scores:

The scores will yet again be calculated for the whole and that of the three subjects separately as mentioned for the initial attempt.

The position or merit list will be accumulated as follows:

  • For the candidates, who have appeared for both the sessions, the better of the two NTA scores will be utilized. Here the overall NTA score will be taken for ranking function and not those of the subjects
  • For the candidates, who have attempted only one exam, the four NTA scores of that attempt will be taken on behalf of the preparation of the merit list
  • The concluding NTA scores will be used to position the candidates and the JEE Main 2019 result acknowledged. If there is any tie, the inter-se-merit principles pointed out before in this piece will be used to decipher it

JEE Main 2019 Rank Declaration

  • The position received as publicized above will be employed for the reason of admittances to NITs, IIITs and GFTIs
  • JEE Main 2019 All India grade and All India Category Rank will be announced on April 30 after the JEE Main II NTA scores are amassed

How the JEE Main 2019 scores for Paper 2 will be calculated

  • Raw marks for the primary effort will be publicized on January 31, 2019, for students who have appeared for the exam conducted in January
  • The authentic marks for the April exam will be declared on April 30 for those who have appeared for the same
  • JEE Main Paper 2 marks will not be regularized as the test will be conducted in a distinct shift, therefore there will be no query of correspondence of the question papers and disparity in complexity stages

Preparation for the Rank List of JEE Main 2019 Paper II

  • The non-analyzed marks for both attempts will be taken into consideration for applicants who have appeared in both the attempts and the better of the marks will be judged
  • For those who have taken only one attempt, the rough marks gained for the same will be used
  • Position lists will be organized as indicated by the marks obtained as stated above

Inter-se-Merit will be prepared as follows:

  • Candidates who attain more marks in the Aptitude Test will be positioned higher
  • If the tie is not settled, those who have scored more marks in Drawing Test will be given the higher position
  • The older candidate will be given the higher rank
  • Last but not least, the tie is still unsettled, the candidates will be given the similar rank

Online Lectures by IIT Professors Uploaded on

NTA has established Test Practice Centres (TPCs) to llow students to acquaint themselves with the CBT (Computer Based Test) mode and gain hands on revision for the upcoming JEE Main and NEET exam. In these test centres, students have a chance to practice mock tests available in Hindi, English and Gujarati Language or else they can download it directly from the official site as well. Now taking it a step forward, NTA has also released the online content based lecture series for all the aspirants going to appear for JEE and NEET exam.

Click Here to Check IIT PAL Lectures

These online lecture series are delivered by the faculty of IITs on the various topics of Physics, Chemistry, Biology and Mathematics. These video lectures are part of IIT PAL (Professor Assisted Learning) and are available on the NTA’s official website and YouTube so that students can easily watch them on their mobile phones as per their convenience.

Highlights for IIT PAL Lectures

  • The average duration of the lecture is about 50 minutes
  • Students can browse the lectures on smartphones with the help of “Swayam” platform
  • Swayam is a part of the MHRD initiative

How to access the IIT PAL lectures?

Video lectures are the major step taken by the NTA and MHRD to facilitate students in the preparation of the exam. All the lectures are provided by the IIT professors according to the examination syllabus. The videos uploaded on the website are segregated subject-wise. To access these video students should follow the below steps:

  • Open the official website of NTA i.e.
  • On the website home page, click on the link named as “Content-Based Lectures”
  • Select any of the particular subjects from Physics, Chemistry, Mathematics and Biology
  • Students will be redirected on YouTube
  • Choose on the specific lecture you want to study

What is Swayam?

It is a government approved direct to home (DTH) channels for providing high-quality educational content to all teachers, students, and more. Every day, a new content is uploaded after four hours.  The lectures are also available on Swayam App for Android and IOS users. The main features of Swayam Prabha are as follows:

  • It covers the content of various disciplines such as arts, science, commerce, performing arts, social sciences and humanities, engineering, technology, etc
  • It covers education of all levels ranging from School education, undergraduate, postgraduate, engineering, and more.

The lectures uploaded by the IIT professors are very descriptive and are almost 1 hour long. The professors have explained each and every concept very clearly with the help of diagrams. It is similar to having an IIT coaching from IIT professors without spending any penny.

Subject-Wise Videos Uploaded

The video lectures uploaded for JEE Main and NEET by the IIT professors cover various topics. The list of the topics covered by various videos in each subject is as follows:


The lectures available are based on topics like refraction at spherical surfaces and by lenses, light, planar motion, kinetics, Kirchhoff’s law, electric energy, and power, drift velocity and resistance, Faraday’s law of induction etc.


Quadratic equations, Limits, Straight lines, Complex Numbers, Three Dimensional Geometry, Permutation and Combination, Circles, Matrices, Statistics, Binomial Theorem etc


Organic Compounds, Redox Reactions, Solutions, Organic Chemistry, Coordination Compounds, States of Matter: Gases and Liquids, Electrochemistry, Chemical Thermodynamics, Polymers etc.


Photosynthesis and Respiration, Cell Structure and Function, Genetics and Evolution, Human Physiology, Ecology, Plant Physiology etc.

Eligibility Criteria for JEE Main Paper 2 Revised

With NTA now at the helm of JEE Main and other national level examinations, eligibility criteria for JEE Main paper 2 has also been revised. JEE Main comprises two papers namely JEE Main paper 1 and JEE Main paper 2. Paper 1 is meant for B.Tech/B.E. aspirants while Paper 2 is meant for B.Arch/B.Planning aspirants. The first phase of JEE Main scheduled from January 6, 2019 till January 20, 2019 while the second phase is scheduled from April 06, 2019 to April 20, 2019

NTA has released an official notification stating the revised criteria for JEE Main Paper 2 aspirants. The Council of Architecture (COA) has amended its Council of Architecture (Minimum Standards of Architectural Education) Regulations, 1983. Let us discuss in detail the JEE Main paper 2 eligibility criteria:

  • Candidate must have Physics, Chemistry, and Mathematics as mandatory subjects in 10th and 12th grade in order to gain admission to the 5 years B.Arch course.
  • Candidate has to score 50% or above marks in Physics, Mathematics and Chemistry in 10th and 12th grade.
  • Also, aspirants needs to score an aggregate of 50% or above in all of the subjects in 10th and 12th grade.

The same had been published in the Official Gazette on June 06, 2017 and comes into force from the academic session 2019-2020. Hence, enforcing the JEE Main paper 2 eligibility criteria.

This addendum change and amendment change has been bought on for the JEE Main paper 2 eligibility criteria by the Central Government. The council informed the National Testing Agency and they are the institution which will conduct the JEE exams from the next academic session of 2019-2020. Also, the reason why the JEE Main paper 2 eligibility criteria are official.

“In view of the modifications in the qualifications prescribed by the Council of Architecture as mentioned above, the eligibility conditions prescribed for admission to B.Arch/B. Planning hereby stands modified,” based on a press release from the National Testing Agency (NTA).

The National Testing Agency has explicitly asked the candidates to ascertain their revised policies prescribed by the Council of Architecture so that the aspiring students for the year of 2019-2020 do not remain blindsided and do not cause any inconvenience at a later stage whilst taking admissions into the 1st year of the 5 year B.Arch course.

The last date for submitting online applications for JEE Main 2019 is 30th September 2018. All the JEE aspirants can apply on the website

Note: Online payment can be done till 1st October 2018. NTA will allow JEE aspirants to edit the application forms from 8th October till 14th October 2018. JEE Main paper 1’s admit card will be released in December and the first bout of the exam is slated to be held in January 2019.

To prepare better for the JEE Main and other exams, the NTA has released a set of online mock tests for Maths and Aptitude. Though there is no mock test available for the drawing section. The aspiring candidates can either download the online mock test or register at the practice centers established by NTA. It has set up about 3084 Test Practice centers (TPCs) across the country for the aspiring candidates to get a hang of the JEE Mains mock test papers.

So, buck up B.Arch applicants and polish up on your syllabus and look through the revised eligibility criteria to be completely prepared.

NTA Releases Official Notification for JEE Main 2019 CBT Exam

JEE Main 2019 Registration closes on September 30. Meanwhile, notification has been released regarding the guidelines for CBT (Computer Based Test) mode exam. From this year onwards, NTA has decided to revoke pen and paper mode. Now, instructions have been released for candidates appearing for JEE Main and other national level entrances managed by NTA.

Let us now have a look at the calendar of events planned for JEE Main 2019 January Session:

  • Registration process for JEE Main 2019 commenced on Sep 1, 2018 and ended on Sep 30, 2018.
  • Payment of fees can be done till Oct 1, 2018 using credit card/debit card/net banking or through challan.
  • In case someone has submitted incorrect details, application correction window would get enabled from Oct 8, 2018 till Oct 14, 2018.
  • Admit card for JEE Main 2019 can be downloaded from official website on Dec 17, 2018.
  • The exam would be held between Jan 6, 2019 and Jan 20, 2019.
  • Declaration of result and cut off would take place on Jan 30, 2019.

Guidelines for JEE Main 2019 CBT Exam

  • To start the exam, candidates need to login on their respective allotted computers using ID and password in the application form.
  • After login, candidates would see a page of instructions which consist of the types of questions, allotted time and marking scheme. Candidates are advised to go through the instructions very carefully at least once.
  • There would be facility of changing the saved answers. You just have to go to the particular question, chose the new option you want to save and click on “save and next”.
  • You can erase an answer too which has been saved previously. Select the question number from question bar and click on “clear response”. Hence the marked answer will get erased.
  • On the top of the computer screen at right hand side, timer would be placed so that the candidates manage their speed accordingly.
  • After the countdown timer reaches zero, the exam would get automatically submitted i.e. the exam will get over by itself and the candidate need not to submit their exam.
  • Unsaved answers of the exam would not be considered for marking procedure.
  • Rough sheets would be provided to the students for doing rough work/calculations.

The main highlights of JEE Main 2019 Exam Pattern are referenced in the table below:

JEE Main Paper I
Exam Mode Computer-based test mode
Exam Duration 3 hours
Subjects Physics, Chemistry, and Mathematics
Total number of questions 90 (Each subject will have 30 questions)
Type of Questions Objective having 4 options each with only 1 correct option
Marking Scheme 4 marks will be awarded for every correct response; for incorrect response 1 mark will be deducted. No marks will be given for unattempted questions.
Maximum Marks Total of 360 Marks
Medium of paper English or Hindi (Candidates from Gujarat, Daman & Diu and Dadra and Nagar Haveli can opt for Gujarati as well)
JEE Main Paper II
Exam Mode Mathematics and Aptitude test will be computer-based, whereas Drawing test will be conducted in pen-and-paper mode
Exam Duration 3 hours
Subjects Mathematics, General Aptitude, and Drawing skills
Total number of questions 82 (Mathematics 30 questions, Aptitude 50 and Drawing 2)
Type of Questions Maths and Aptitude will be objective type while drawing section will have questions to test the drawing and sketching skills
Marking Scheme 4 marks will be awarded for every correct response; for incorrect response 1 mark will be deducted. No marks will be given for unattempted questions.
Maximum Marks Total of 390 Marks (Drawing section will be of total 70 marks, marking of every question will be given along with it.)
Medium of paper English or Hindi (Candidates from Gujarat, Daman & Diu and Dadra and Nagar Haveli can opt for Gujarati as well)

Latest Changes Introduced in JEE Main

  • Exams would be conducted by NTA (National Test Agency) replacing CBSE as the new organizing authority.
  • The exam would be held in just online mode from this year. Pen and paper mode would not be used any further.
  • Practice centers has been set up for the students across the country so that they make take free mocks and get an idea of the main exam and learn to deal with the pressure of the examination hall so that it may be rectified.
  • Online lectures will be provided by IIT professors on every subject and candidates may avail the facility according to their level of preparation.

BITSAT 2019: Application Form, Exam Date, Syllabus

BITSAT 2019 Slot booking process will starts from fourth week of March to first week of April 2019. BITSAT commonly named as Birla Institute of Technology and Science Aptitude Test is carried out by Birla Institute of Technology and Science (BITS) to admit the candidates who wants to pursue their career in engineering or medicines. BITSAT is a university level examination. This is a computer based exam which the candidates needs to clear to get the seat reserved for him/her in BITS campuses at Pilani, Goa and Hyderabad. BITSAT is a one of step forward for the candidates who want to pursue their carrier in BE honors at BITS campus in programmes like Civil Engineering, Computer Science Engineering, Electrical and Economics, Mechanical Engineering and Chemical Engineering. The application starts from third week of Dec 2018 till second week of March 2019. (more…)

NTA: Aadhaar not Mandatory for JEE Main Registration

National Testing Agency (NTA) in an official notification released on September 12, 2019 clarified that the 12 digit identification number, Aadhar number is not mandatory for JEE Main 2019 and UGC-NET 2018 registration. NTA is the new nodal agency operating under the Department of Higher Education, Ministry of Human Resource Development (HRD), Government of India. It is the new conducting body for UGC-NET 2018 and JEE Main 2019 besides several other entrance exams.

JEE Main 2019 and UGC-NET 2018 registration has begun from September 01, 2018 and will close on September 30, 2018. However, NTA will conduct JEE Main in online mode twice a year. The first phase of JEE Main 2019 will be held from January 06, 2019 to January 20, 2019. Based on the increasing number of queries received about mandatory filling in the Aadhar number in UGC-NET 2018 registration form, NTA released this notice.

In this context, NTA released a statement stating, “It is thus simplified that during the online registration process while filling in online Application Form, the Aadhar number is just one of the many types of identification required, it is not mandatory, as per the ‘Replica of Application Form’ mentioned in Annexure VIII (page 39-40) (UGC-NET Bulletin December 2018) in the drop down box related to ‘Identification Type’ and as also mentioned on page 11.

JEE Main 2019 Aadhaar Notice

Applicants can give their ration card number, passport number, bank account number or any other relevant government identity number, according to the information provided on page 11 of the December 2018 edition of UGC-NET Bulletin.

Candidates are required to provide their ID card number, Name, Date of Birth and Gender and other important details in the application form. Also, those who want to give their Aadhar number during the registration shall check and conform to any of the following conditions.

Condition I:

Aspirants, who have not yet applied for Aadhaar, must submit the application for the same and visit the facilitation center for enrolment. Candidates can visit any facilitation center or Aadhaar enrollment center to get enrolled.  The enrolment process is free of cost.

For the convenience of the candidates, the board has set up facilitation center in every examination city for Aadhaar enrolment.

Condition II:

Those who have applied for Aadhaar and have to get it yet must fill 14 digits Aaddhaar Enrollment ID mentioned on their Aadhaar enrollment slip during registration.

Condition III:

In case the facilitation center does not provide Aadhaar enrollment facility, candidates must send a request for Aadhaar Enrollment.

Candidates will be provided with a registration number by the facilitation center, and they can fill in the registration number when filling the registration form.

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